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JEE Main & Advanced Physics Electrostatics & Capacitance Question Bank Electric Field and Potential

  • question_answer
    A charged particle of mass \[5\times {{10}^{-5}}kg\] is held stationary in space by placing it in an electric field of strength \[{{10}^{7}}N{{C}^{-1}}\] directed vertically downwards. The charge on the particle is [EAMCET 2000]

    A)            \[-20\times {{10}^{-5}}\mu C\]

    B)                                      \[-5\times {{10}^{-5}}\mu C\]

    C)            \[5\times {{10}^{-5}}\mu C\]

    D)                                      \[20\times {{10}^{-5}}\mu C\]

    Correct Answer: B

    Solution :

                         QE = mg \[\Rightarrow \,Q=\frac{mg}{E}=\frac{5\times {{10}^{-5}}\times 10}{{{10}^{7}}}\]\[=5\times {{10}^{5}}mC\]. Since electric field is acting downward so for balance charge must be negative.


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