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JEE Main & Advanced Physics Electrostatics & Capacitance Question Bank Electric Field and Potential

  • question_answer
    An electron of mass \[m\] and charge \[e\] is accelerated from rest through a potential difference V in vacuum. The final speed of the electron will be                                              [MP PMT 2000; AMU (Engg.) 2000]

    A)            \[V\sqrt{e/m}\]

    B)                                      \[\sqrt{eV/m}\]

    C)            \[\sqrt{2eV/m}\]

    D)                                      \[2eV/m\]

    Correct Answer: C

    Solution :

                 Kinetic energy \[K=\frac{1}{2}m{{v}^{2}}=eV\]Þ \[v=\sqrt{\frac{2eV}{m}}\]


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