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JEE Main & Advanced Physics Electrostatics & Capacitance Question Bank Electric Field and Potential

  • question_answer
    A uniform electric field having a magnitude \[{{E}_{0}}\] and direction along the positive \[X-\]axis exists. If the potential \[V\] is zero at \[x=0\], then its value at \[X=+x\] will be [MP PMT 1987]

    A)                    \[{{V}_{(x)}}=+x{{E}_{0}}\]

    B)                                      \[{{V}_{x}}=-x{{E}_{0}}\]

    C)                    \[{{V}_{x}}=+{{x}^{2}}{{E}_{0}}\]

    D)                                      \[{{V}_{x}}=-{{x}^{2}}{{E}_{0}}\]

    Correct Answer: B

    Solution :

                 \[\because \,E=-\frac{dV}{dX}\] Þ \[{{V}_{x}}=-x{{E}_{0}}\]


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