JEE Main & Advanced Physics Electrostatics & Capacitance Question Bank Electric Field and Potential

  • question_answer
    A particle of mass ?m? and charge ?q? is accelerated through a potential difference of V volt, its energy will be [MP PET 2001]

    A)            \[qV\]                                     

    B)            \[mqV\]

    C)            \[\left( \frac{q}{m} \right)V\]

    D)                    \[\frac{q}{mV}\]

    Correct Answer: A

    Solution :

                 KE = qV


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