A) \[\frac{Q}{R}\]
B) \[\frac{Q}{x}\]
C) \[\frac{Q}{{{x}^{2}}}\]
D) \[xQ\]
Correct Answer: A
Solution :
Potential at any point inside the charged spherical conductor equals to the potential at the surface of the conductor i.e. Q/R.
You need to login to perform this action.
You will be redirected in
3 sec
