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JEE Main & Advanced Physics Electrostatics & Capacitance Question Bank Electric Field and Potential

  • question_answer
    A ball of mass 1 g and charge \[{{10}^{-8}}C\] moves from a point A. where potential is 600 volt to the point B where potential is zero. Velocity of the ball at the point B is 20 cm/s. The velocity of the ball at the point A will be            [KCET 2001]

    A)            22.8 cm/s

    B)                                      228 cm/s

    C)            16.8 m/s                                 

    D)            168 m/s

    Correct Answer: A

    Solution :

                         By using \[\frac{1}{2}m(v_{1}^{2}-v_{2}^{2})=QV\] Þ \[\frac{1}{2}\times {{10}^{-3}}\{v_{1}^{2}-{{(0.2)}^{2}}\}={{10}^{-8}}(600-0)\] Þ \[{{v}_{1}}=22.8\,cm/s\]


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