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JEE Main & Advanced Physics Electrostatics & Capacitance Question Bank Electric Field and Potential

  • question_answer
    The acceleration of an electron in an electric field of magnitude 50 V/cm, if e/m value of the electron is \[1.76\times {{10}^{11}}\]C/kg, is                                                     [CPMT 2001]

    A)            \[8.8\times {{10}^{14}}\]m/sec2

    B)            \[6.2\times {{10}^{13}}\] m/sec2

    C)            \[5.4\times {{10}^{12}}\] m/sec2                                     

    D)            Zero

    Correct Answer: A

    Solution :

                 \[a=\frac{eE}{m}\Rightarrow \,a=1.76\times {{10}^{11}}\times 50\times {{10}^{2}}\] \[=8.8\times {{10}^{14}}m/se{{c}^{2}}\]        


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