JEE Main & Advanced Physics Electrostatics & Capacitance Question Bank Electric Field and Potential

  • question_answer
    Kinetic energy of an electron accelerated in a potential difference of 100 V is      [AFMC 1999; MP PMT 2002]

    A)                                             \[1.6\times {{10}^{-17}}\]J

    B)                                                          \[1.6\times {{10}^{21}}\]J

    C)            \[1.6\times {{10}^{-29}}\]J     

    D)            \[1.6\times {{10}^{-34}}\]J                               

    Correct Answer: A

    Solution :

                         By using \[KE=QV\Rightarrow KE=\text{ }1.6\times {{10}^{19}}\times 100\] \[=\text{ }1.6\times {{10}^{17}}J\]


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