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JEE Main & Advanced Physics Electrostatics & Capacitance Question Bank Electric Field and Potential

  • question_answer
    An \[\alpha \]-particle is accelerated through a potential difference of 200V. The increase in its kinetic energy is                                                                                            [UPSEAT 2002]

    A)            100 eV                                     

    B)            200 eV

    C)            400 eV

    D)            800 eV

    Correct Answer: C

    Solution :

                 \[KE=QV\,\Rightarrow KE=(2e)\,200\,V=400\,eV\]


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