A) \[\frac{E{{q}^{2}}m}{2{{t}^{2}}}\]
B) \[\frac{2{{E}^{2}}{{t}^{2}}}{mq}\]
C) \[\frac{{{E}^{2}}{{q}^{2}}{{t}^{2}}}{2m}\]
D) \[\frac{Eqm}{t}\]
Correct Answer: C
Solution :
When charge q is released in uniform electric field \[E\] then its acceleration \[a=\frac{qE}{m}\] (is constant) So its motion will be uniformly accelerated motion and its velocity after time t is given by \[v=at\]\[=\frac{qE}{m}t\] Þ KE \[=\frac{1}{2}m{{v}^{2}}=\frac{1}{2}\,{{\left( \frac{qE}{m}t \right)}^{2}}=\frac{{{q}^{2}}{{E}^{2}}{{t}^{2}}}{2m}\]
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