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JEE Main & Advanced Physics Electrostatics & Capacitance Question Bank Electric Field and Potential

  • question_answer
    A proton is about 1840 times heavier than an electron. When it is accelerated by a potential difference of 1 kV, its kinetic energy will be                                 [AIIMS 2003; DCE 2001]

    A)            1840 keV

    B)                                      1/1840 keV

    C)            1 keV                                       

    D)            920 keV

    Correct Answer: C

    Solution :

                 \[KE=QV\]\[=e\times {{10}^{3}}V=\text{ }1KeV\].


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