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JEE Main & Advanced Physics Electrostatics & Capacitance Question Bank Electric Field and Potential

  • question_answer
    The electric potential at the surface of an atomic nucleus (Z = 50) of radius \[9.0\times ~{{10}^{-13}}cm\]is                              [CPMT 1990; Pb. PMT 2002; BVP 2003; MP PET 2004]

    A)            80 volts

    B)                                      \[8\times {{10}^{6}}\]volts

    C)            9 volts                                     

    D)            \[9\times {{10}^{5}}\]volts

    Correct Answer: B

    Solution :

                 \[V=9\times {{10}^{9}}\times \frac{50\times 1.6\times {{10}^{-19}}}{9\times {{10}^{-15}}}=8\times {{10}^{6}}V\]


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