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JEE Main & Advanced Physics Electrostatics & Capacitance Question Bank Electric Field and Potential

  • question_answer
    A charge of 10 e.s.u. is placed at a distance of 2 cm from a charge of 40 e.s.u. and 4 cm from another charge of 20 e.s.u. The potential energy of the charge 10 e.s.u. is (in ergs) [CPMT 1976; MP PET 1989]

    A)            87.5                                          

    B)            112.5

    C)            150

    D)            250

    Correct Answer: D

    Solution :

                 Energy \[=\frac{10\times 40}{2}+\frac{10\times 20}{4}=250\,\,erg\]


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