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JEE Main & Advanced Physics Electrostatics & Capacitance Question Bank Electric Field and Potential

  • question_answer
    When a charge of 3 coulombs is placed in a uniform electric field, it experiences a force of 3000 Newton. Within this field, potential difference between two points separated by a distance of 1 cm is             [MP PMT 1986; 2000]

    A)            10 volts

    B)                                      90 volts

    C)                    1000 volts                      

    D)            3000 volts

    Correct Answer: A

    Solution :

                 \[V=Ed=\frac{3000}{3}\times {{10}^{-2}}=10V\]


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