A) Decreases
B) Increases
C) Remains unchanged
D) Becomes zero
Correct Answer: B
Solution :
Potential energy of the system will be given by \[=\frac{(-e)\,(-e)}{4\pi {{\varepsilon }_{0}}r}=\frac{{{e}^{2}}}{4\pi {{\varepsilon }_{0}}r}\] As r decreases, potential energy increases.
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