JEE Main & Advanced Physics Electrostatics & Capacitance Question Bank Electric Field and Potential

  • question_answer
    The magnitude of electric field intensity \[E\] is such that, an electron placed in it would experience an electrical force equal to its weight is given by                                                [CPMT 1975, 80; AFMC 2001; BCECE 2003]

    A)                    \[mge\]

    B)                                      \[\frac{mg}{e}\]

    C)                    \[\frac{e}{mg}\]

    D)                                      \[\frac{{{e}^{2}}}{{{m}^{2}}}g\]

    Correct Answer: B

    Solution :

                 According to the question, \[eE=mg\] Þ \[E=\frac{mg}{e}\]


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