A) 0
B) \[\frac{Q}{8\pi {{\varepsilon }_{0}}R}\]
C) \[\frac{Q}{4\pi {{\varepsilon }_{0}}R}\]
D) \[\frac{Q}{2\pi {{\varepsilon }_{0}}R}\]
Correct Answer: C
Solution :
Potential inside the conducting sphere is same as that of surface i.e. \[\frac{Q}{4\pi {{\varepsilon }_{0}}R}\]
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