A) Zero
B) \[\frac{Qq}{4\pi {{\in }_{0}}a}\]
C) \[\frac{Qq\sqrt{2}}{4\pi {{\in }_{0}}a}\]
D) \[\frac{Qq}{2\pi {{\in }_{0}}a}\]
Correct Answer: A
Solution :
From symmetry of the figure all corner have same electric potential. Therefore work done in moving the charge q from the corner to the diagonally opposite corner is zero.You need to login to perform this action.
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