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JEE Main & Advanced Physics Electrostatics & Capacitance Question Bank Electric Field and Potential

  • question_answer
    An electron experiences a force equal to its weight when placed in an electric field. The intensity of the field will be                                                                                            [MHCET 2004]

    A)                    \[1.7\times {{10}^{-11}}\,N/C\]

    B)                                      \[5.0\times {{10}^{-11}}\,N/C\]

    C)                    \[5.5\times {{10}^{-11}}\,N/C\]

    D)            56 N/C

    Correct Answer: C

    Solution :

                 \[E=\frac{F}{q}=\frac{mg}{e}\] \[=\frac{9\times {{10}^{-31}}\times 9.8}{1.6\times {{10}^{-19}}}=5.5\times {{10}^{-11}}N/C\]                          


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