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JEE Main & Advanced Physics Electrostatics & Capacitance Question Bank Electric Field and Potential

  • question_answer
    The dielectric strength of air at NTP is \[3\times {{10}^{6}}\,V/m\] then the maximum charge that can be given to a spherical conductor of radius 3 m is                                                                         [Pb. PMT 2001]

    A)            \[3\times {{10}^{-4}}C\]

    B)                                      \[3\times {{10}^{-3}}C\]

    C)            \[3\times {{10}^{-2}}C\]

    D)                                      \[3\times {{10}^{-1}}C\]

    Correct Answer: B

    Solution :

                         By using \[E=9\times {{10}^{9}}\times \frac{Q}{{{R}^{2}}}\] Þ \[3\times {{10}^{6}}=9\times {{10}^{9}}\times \frac{Q}{{{(3)}^{2}}}\] Þ \[Q=\text{ }3\times {{10}^{3}}C\]


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