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JEE Main & Advanced Physics Electrostatics & Capacitance Question Bank Electric Field and Potential

  • question_answer
    Two parallel plates have equal and opposite charge. When the space between them is evacuated, the electric field between the plates is \[2\times {{10}^{5}}V/m\]. When the space is filled with dielectric, the electric field becomes\[1\times {{10}^{5}}V/m\]. The dielectric constant of the dielectric material      [MP PET 1989]

    A)                    1/2

    B)                                      1

    C)                    2

    D)                                      3

    Correct Answer: C

    Solution :

                 \[K=\frac{{{E}_{\text{without dielectric }}}}{{{E}_{\text{with dielectric}}}}=\frac{2\times {{10}^{5}}}{1\times {{10}^{5}}}=2\]


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