A) \[\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{Qq}{l}\]
B) \[\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{Qq}{{{l}^{2}}}\]
C) \[\frac{1}{4\pi {{\varepsilon }_{0}}}Qql\]
D) Zero
Correct Answer: D
Solution :
According to figure, potential at A and C are equal. Hence work done in moving ? q charge from A to C is zero.You need to login to perform this action.
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