A) ? 13.6 V
B) ? 27.2 V
C) 27.2 V
D) 13.6 V
Correct Answer: C
Solution :
\[V=9\times {{10}^{9}}\times \frac{Q}{r}=9\times {{10}^{9}}\times \frac{(+1.6\times {{10}^{-19}})}{0.53\times {{10}^{-10}}}\]= 27.2VYou need to login to perform this action.
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