A) 18 N
B) 1.8 N
C) 0.18 N
D) None of the above
Correct Answer: B
Solution :
In the following figure, in equilibrium\[{{F}_{e}}=Tsin\text{ }{{30}^{o}}\], r = 1m Þ \[9\times {{10}^{9}}.\frac{{{Q}^{2}}}{{{r}^{2}}}\]=\[T\times \frac{1}{2}\] Þ \[9\times {{10}^{9}}.\frac{{{(10\times {{10}^{-6}})}^{2}}}{{{1}^{2}}}=T\times \frac{1}{2}\] \[\Rightarrow \]T = 1.8 NYou need to login to perform this action.
You will be redirected in
3 sec