A) Decreases
B) Increases
C) Remains unchanged
D) Becomes zero
Correct Answer: B
Solution :
Potential energy of the system will be given by \[=\frac{(-e)\,(-e)}{4\pi {{\varepsilon }_{0}}r}=\frac{{{e}^{2}}}{4\pi {{\varepsilon }_{0}}r}\] As r decreases, potential energy increases.You need to login to perform this action.
You will be redirected in
3 sec