A) + 2kV
B) ? 2 kV
C) + 200 V
D) ? 200 V
Correct Answer: A
Solution :
Work done \[W=Q({{V}_{B}}-{{V}_{A}})\Rightarrow \,({{V}_{B}}-{{V}_{A}})=\frac{W}{Q}\] \[=\frac{10\times {{10}^{-3}}}{5\times {{10}^{-6}}}J/C=2\,kV\]You need to login to perform this action.
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