A) 3.2 × 10?10 J
B) 3.2 × 10?18 J
C) 1 N
D) 1 dyne
Correct Answer: B
Solution :
\[\,\text{K}\text{.E}\text{.}\,={{q}_{0}}({{V}_{A}}-{{V}_{B}})=1.6\times {{10}^{-19}}(70-50)=3.2\times {{10}^{-18}}J\]
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