A) \[{{V}_{(x)}}=+x{{E}_{0}}\]
B) \[{{V}_{x}}=-x{{E}_{0}}\]
C) \[{{V}_{x}}=+{{x}^{2}}{{E}_{0}}\]
D) \[{{V}_{x}}=-{{x}^{2}}{{E}_{0}}\]
Correct Answer: B
Solution :
\[\because \,E=-\frac{dV}{dX}\] Þ \[{{V}_{x}}=-x{{E}_{0}}\]You need to login to perform this action.
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