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JEE Main & Advanced Physics Electrostatics & Capacitance Question Bank Electric Field and Potential

  • question_answer
    If \[E\] is the electric field intensity of an electrostatic field, then the electrostatic energy density is proportional to                                                                                          [MP PMT 2003]

    A)                    \[E\]

    B)                                      \[{{E}^{2}}\]

    C)                    \[1/{{E}^{2}}\]

    D)                                      \[{{E}^{3}}\]

    Correct Answer: B

    Solution :

        Electrostatic energy density \[\frac{dU}{dV}=\frac{1}{2}K{{\varepsilon }_{0}}{{E}^{2}}\] \ \[\frac{dU}{dV}\propto {{E}^{2}}\]


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