A) \[2.7\times {{10}^{5}}\]
B) \[2.6\times {{10}^{5}}\]
C) \[2.5\times {{10}^{5}}\]
D) \[2.4\times {{10}^{5}}\]
Correct Answer: C
Solution :
\[E=\frac{1}{4\pi {{\varepsilon }_{0}}}.\frac{ne}{{{r}^{2}}}\] Þ \[n=\frac{E{{r}^{2}}}{e}.4\pi {{\varepsilon }_{0}}\] Þ \[n=\frac{0.036\times 0.1\times 0.1}{9\times {{10}^{9}}\times 1.6\times {{10}^{-19}}}=\frac{360}{144}\times {{10}^{5}}\]= 2.5 ´ 105 N/C.You need to login to perform this action.
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