A) Zero
B) Infinite
C) \[27\,J\]
D) \[100\,J\]
Correct Answer: C
Solution :
For pair of charge \[U=\frac{1}{4\pi {{\varepsilon }_{0}}}.\frac{{{q}_{1}}{{q}_{2}}}{r}\] \[{{U}_{System}}=\frac{1}{4\pi {{\varepsilon }_{0}}}\left[ \frac{10\times {{10}^{-6}}\times 10\times {{10}^{-6}}}{10/100} \right.\]\[\left. +\frac{10\times {{10}^{-6}}\times 10\times {{10}^{-6}}}{10/100}+\frac{10\times {{10}^{-6}}\times 10\times {{10}^{-6}}}{10/100} \right]\] \[=3\times 9\times {{10}^{9}}\times \frac{100\times {{10}^{-12}}\times 100}{10}=27J\]You need to login to perform this action.
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