A) \[e\]
B) \[3e\]
C) \[6e\]
D) \[8e\]
Correct Answer: B
Solution :
For equilibrium mg = qE \ \[1.96\times {{10}^{-15}}\times 9.8=q\times \,\left( \frac{800}{0.02} \right)\] Þ \[q=\frac{1.96\times {{10}^{-15}}\times 9.8\times 0.02}{800}\] Þ \[n\times 1.6\times {{10}^{-19}}=\frac{1.96\times {{10}^{-15}}\times 9.8\times 0.02}{800}\]Þ n = 3.You need to login to perform this action.
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