JEE Main & Advanced Physics Electrostatics & Capacitance Question Bank Electric Field and Potential

  • question_answer
    The intensity of the electric field required to keep a water drop of radius \[{{10}^{-5}}cm\] just suspended in air when charged with one electron is approximately [MP PMT 1994]

    A)            \[260\,volt/cm\]

    B)                                      \[260\,newton/coulomb\]

    C)                    \[130\,volt/cm\]

    D)                                      \[130\,newton/coulomb\]            \[(g=10\,newton/kg,\,e=1.6\times {{10}^{-19}}coulomb)\]

    Correct Answer: B

    Solution :

                 For balance \[mg=eE\] Þ \[E=\frac{mg}{e}\] Also \[m=\frac{4}{3}\pi \,{{r}^{3}}d=\frac{4}{3}\times \frac{22}{7}\times {{({{10}^{-7}})}^{3}}\times 1000\,kg\] Þ \[E=\frac{4/3\times 22/7\times {{({{10}^{-7}})}^{3}}\times 1000\times 10}{1.6\times {{10}^{-19}}}\]= 260 N/C


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