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JEE Main & Advanced Physics Electrostatics & Capacitance Question Bank Electric Field and Potential

  • question_answer
    A mass \[m=20\,g\] has a charge \[q=3.0\,mC\]. It moves with a velocity of \[20\,m/s\] and enters a region of electric field of \[80\,N/C\]in the same direction as the velocity of the mass. The velocity of the mass after 3 seconds in this region is

    A)            \[80\,m/s\]

    B)                                      \[56\,m/s\]

    C)                    \[44\,m/s\]

    D)                                      \[40\,m/s\]

    Correct Answer: B

    Solution :

                         \[a=\frac{QE}{m}=\frac{3\times {{10}^{-3}}\times 80}{20\times {{10}^{-3}}}=12\,m/se{{c}^{2}}\] Hence v = u + at Þ v = 20 + 12 ´ 3 = 56 m/s.


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