A) \[150\sqrt{2}\,volt\]
B) \[1500\sqrt{2}\,volt\]
C) \[900\sqrt{2}\,volt\]
D) \[900\,volt\]
Correct Answer: B
Solution :
Potential at the centre O, \[V=4\times \frac{1}{4\pi {{\varepsilon }_{0}}}.\frac{Q}{a/\sqrt{2}}\] where \[Q=\frac{10}{3}\times {{10}^{-9}}C\] and \[a=8\,cm\,=\,\,8\times {{10}^{-2}}m\] So \[V=5\times 9\times {{10}^{9}}\times \frac{\frac{10}{3}\times {{10}^{-9}}}{\frac{8\times {{10}^{-2}}}{\sqrt{2}}}\]\[=1500\sqrt{2}\,volt\]You need to login to perform this action.
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