A) \[\frac{{{q}^{2}}}{8\pi {{\varepsilon }_{0}}a}\]
B) \[\frac{6{{q}^{2}}}{8\pi {{\varepsilon }_{0}}a}\]
C) \[-\frac{7{{q}^{2}}}{8\pi {{\varepsilon }_{0}}a}\]
D) \[\frac{9{{q}^{2}}}{8\pi {{\varepsilon }_{0}}a}\]
Correct Answer: C
Solution :
\[{{U}_{system}}=\frac{1}{4\pi {{\varepsilon }_{0}}}\,\frac{(q)\,(-2q)}{a}+\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{(-2q)\,(q)}{a}+\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{(q)\,(q)}{2a}\] \[{{U}_{system}}=-\frac{7\,{{q}^{2}}}{8\pi {{\varepsilon }_{0}}a}\]
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