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JEE Main & Advanced Physics Electrostatics & Capacitance Question Bank Electric Field and Potential

  • question_answer
    An alpha particle is accelerated through a potential difference of \[{{10}^{6}}\,volt\]. Its kinetic energy will be                                                                                   [MP PMT/PET 1998]

    A)                    \[1\,MeV\]

    B)                                      \[2\,MeV\]

    C)                    \[4\,MeV\]

    D)                                      \[8\,MeV\]

    Correct Answer: B

    Solution :

                 \[K=qV=2e\times {{10}^{6}}J=\frac{2e\times {{10}^{6}}}{e}eV=2MeV\]


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