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JEE Main & Advanced Physics Electrostatics & Capacitance Question Bank Electric Field and Potential

  • question_answer
    An electron of mass \[{{m}_{e}}\] initially at rest moves through a certain distance in a uniform electric field in time \[{{t}_{1}}\]. A proton of mass \[{{m}_{p}}\] also initially at rest takes time \[{{t}_{2}}\] to move through an equal distance in this uniform electric field. Neglecting the effect of gravity, the ratio of \[{{t}_{2}}/{{t}_{1}}\] is nearly equal to                                                                  [IIT 1997 Cancelled]

    A)                    1

    B)                                      \[{{({{m}_{p}}/{{m}_{e}})}^{1/2}}\]

    C)                    \[{{({{m}_{e}}/{{m}_{p}})}^{1/2}}\]

    D)                                      1836

    Correct Answer: B

    Solution :

                         For electron \[s=\frac{eE}{{{m}_{e}}}\times t_{1}^{2}\],  For proton \[s=\frac{eE}{{{m}_{p}}}\times t_{2}^{2}\] \ \[\frac{t_{2}^{2}}{t_{1}^{2}}=\frac{{{m}_{p}}}{{{m}_{e}}}\,\Rightarrow \frac{{{t}_{2}}}{{{t}_{1}}}=\sqrt{\frac{{{m}_{p}}}{{{m}_{e}}}}={{\left( \frac{{{m}_{p}}}{{{m}_{e}}} \right)}^{1/2}}\]


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