A) \[1.02\times {{10}^{7}}N/C\] upwards
B) \[2.04\times {{10}^{7}}N/C\] downwards
C) \[2.04\times {{10}^{7}}N/C\] upwards
D) \[1.02\times {{10}^{7}}N/C\] downwards
Correct Answer: A
Solution :
Side a = 5 ´ 10?2 m Half of the diagonal of the square \[r=\frac{a}{\sqrt{2}}\] Electric field at centre due to charge q \[E=\frac{kq}{{{\left( \frac{a}{\sqrt{2}} \right)}^{2}}}\]You need to login to perform this action.
You will be redirected in
3 sec