A) 2.8 J
B) 3.5 J
C) 4.5 J
D) 5.5 J
Correct Answer: A
Solution :
Work done \[W=3\times {{10}^{-6}}({{V}_{A}}-{{V}_{B}});\] where \[{{V}_{A}}={{10}^{10}}\left[ \frac{(-5\times {{10}^{-6}})}{15\times {{10}^{-2}}}+\frac{2\times {{10}^{-6}}}{5\times {{10}^{-2}}} \right]=\frac{1}{15}\times {{10}^{6}}\,volt\] and \[{{V}_{B}}={{10}^{10}}\left[ \frac{(2\times {{10}^{-6}})}{15\times {{10}^{-2}}}-\frac{5\times {{10}^{-6}}}{5\times {{10}^{-2}}} \right]=-\frac{13}{15}\times {{10}^{6}}\,volt\] \ \[W=3\times {{10}^{-6}}\left[ \frac{1}{15}\times {{10}^{6}}-\left( -\frac{13}{15}\times {{10}^{6}} \right) \right]\]= 2.8 JYou need to login to perform this action.
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