A) \[\left( -\frac{q}{2} \right)\]
B) \[(-q)\]
C) \[(+q)\]
D) Zero
Correct Answer: A
Solution :
Potential energy of the system \[U=k\frac{Qq}{l}+\frac{k{{q}^{2}}}{l}+\frac{kqQ}{l}=0\] Þ \[\frac{kq}{l}(Q+q+Q)=0\] Þ \[Q=-\frac{q}{2}\]You need to login to perform this action.
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