JEE Main & Advanced
Physics
Electrostatics & Capacitance
Question Bank
Electric Field and Potential
question_answer
The work done in bringing a 20 coulomb charge from point A to point B for distance 0.2m is 2J. The potential difference between the two points will be (in volt) [RPET 1999; MP PMT 2002; AIEEE 2002]
A) 0.2
B) 8
C) 0.1
D) 0.4
Correct Answer:
C
Solution :
By using \[W=Q.\Delta V\]Þ \[\Delta V=\frac{2}{20}=0.1\,volt\]