2. Questions Bank
  3. JEE Main & Advanced
  4. Physics
  5. Electrostatics & Capacitance

JEE Main & Advanced Physics Electrostatics & Capacitance Question Bank Electric Field and Potential

  • question_answer
    Two point charges of \[20\,\mu \,C\] and \[80\,\mu \,C\] are \[10\,cm\] apart. Where will the electric field strength be zero on the line joining the charges from \[20\,\mu \,C\] charge         [RPET 1997]

    A)                    \[0.1\,m\]

    B)                                      \[0.04\,m\]

    C)                    \[0.033\,m\]

    D)                                      \[0.33\,m\]

    Correct Answer: C

    Solution :

                 Let neutral point be obtained at a distance x from 20 mC charge. Hence at neutral point \[\frac{20}{{{(x)}^{2}}}=\frac{80}{{{(10-x)}^{2}}}\] Þ \[x=+\,0.033\,m\]


You need to login to perform this action.
You will be redirected in 3 sec spinner