JEE Main & Advanced Physics Electrostatics & Capacitance Question Bank Electric Field and Potential

  • question_answer
    A proton is accelerated through 50,000 V. Its energy will increase by                                        [JIPMER 1999]

    A)            5000 eV

    B)                                      \[8\times {{10}^{-15}}\]J

    C)            5000 J                                      

    D)            50,000 J

    Correct Answer: B

    Solution :

                         Kinetic energy \[K=Q.V\Rightarrow K=\text{ }\left( +e \right)\text{ }\left( 50000V \right)\] \[=\text{ }50000eV=\text{ }50000\times 1.6\times {{10}^{19}}J=\text{ }8\times {{10}^{15}}J\]


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