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JEE Main & Advanced Physics Electrostatics & Capacitance Question Bank Electric Field and Potential

  • question_answer
    When a proton is accelerated through 1V, then its kinetic energy will be                                                [CBSE PMT 1999]

    A)            1840 eV

    B)                                      13.6 eV

    C)            1 eV

    D)            0.54 eV

    Correct Answer: C

    Solution :

                 \[\Delta \,KE=qV=eV=e\times 1=1eV\]                       


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