JEE Main & Advanced Physics Electrostatics & Capacitance Question Bank Electric Field and Potential

  • question_answer
    Two positive point charges of \[12\mu C\] and \[8\mu C\] are 10cm apart. The work done in bringing them 4 cm closer is [AMU 2000]

    A)            5.8 J                                         

    B)            5.8 eV

    C)            13 J

    D)            13 eV

    Correct Answer: C

    Solution :

                         \[W={{U}_{f}}-{{U}_{i}}=9\times {{10}^{9}}\times {{Q}_{1}}\,{{Q}_{2}}\left[ \frac{1}{{{r}_{2}}}-\frac{1}{{{r}_{1}}} \right]\] Þ\[W=9\times {{10}^{9}}\times 12\times {{10}^{-6}}\times 8\times {{10}^{-6}}\left[ \frac{1}{4\times 10{{\,}^{-2}}}-\frac{1}{10\,\times 10{{\,}^{-2}}} \right]\]        = 12.96 J » 13 J           


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