A) \[8\times {{10}^{-12}}\]N
B) \[8\times {{10}^{-14}}\]N
C) \[8\times {{10}^{9}}\] N
D) \[8\times {{10}^{14}}\] N
Correct Answer: B
Solution :
Force on electron F = QE \[=Q\,\left( \frac{V}{d} \right)\] Þ \[F=(1.6\times {{10}^{-19}})\,\left( \frac{1000}{2\times {{10}^{-3}}} \right)=8\times {{10}^{-14}}N\]You need to login to perform this action.
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