A) \[E\propto {{R}^{-2}}\]
B) \[E\propto {{R}^{-1}}\]
C) \[E\propto \frac{1}{{{R}^{3}}}\]
D) \[E\propto {{R}^{2}}\]
Correct Answer: C
Solution :
\[E=\frac{1}{4\pi {{\varepsilon }_{0}}}.\frac{Qr}{{{R}^{3}}}\] Þ \[E\propto \frac{1}{{{R}^{3}}}\]
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