A) \[\frac{3}{8}\] ampere
B) 2 ampere
C) \[\frac{1}{2}\] ampere
D) \[\frac{1}{8}\] ampere
Correct Answer: A
Solution :
Redraw the diagram with battery and the resistance in the common branch as the lower branch as shown below: \[{{R}_{eq}}=\frac{4}{3}+4=\frac{16}{3}\] \[I=\frac{V}{{{R}_{eq}}}=2\times \frac{3}{16}=\frac{3}{8}\]You need to login to perform this action.
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