A) \[{{V}_{1}}={{V}_{2}}={{V}_{3}}\]
B) \[{{V}_{1}}={{V}_{2}}>{{V}_{3}}\]
C) \[{{V}_{1}}<{{V}_{2}}<{{V}_{3}}\]
D) \[{{V}_{1}}={{V}_{2}}<{{V}_{3}}\]
Correct Answer: D
Solution :
Total potential difference across resistances is \[V={{V}_{1}}+{{V}_{2}}+{{V}_{3}}\] Since the resistances are connected in series, the same current flow through each resistance and\[{{R}_{1}}={{R}_{2}}={{R}_{3}}=R\] \[\therefore \] \[{{V}_{1}}=l{{R}_{1}}=lR\] \[{{V}_{2}}=l{{R}_{2}}=lR\] \[{{V}_{3}}=l({{R}_{3}}+{{R}_{4}})=l(R+R)=2lR\] \[\therefore \] \[{{V}_{1}}={{V}_{2}}<{{V}_{3}}\]You need to login to perform this action.
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